Let in a binomial distribution consisting of 5 independent

Last updated: 5/27/2023

Let in a binomial distribution consisting of 5 independent trials probabilities of exactly 1 and 2 successes be 0 4 and 0 6 respectively Then the probability of getting exactly 3 successes is equal to O 2160 74 O 4320 74 O 4320 75 O 2160 75