News reports indicate that nationally, 45% of Americans are

Last updated: 7/11/2022

News reports indicate that nationally, 45% of Americans are planning "staycations" at home this year instead of a vacation trip. Suppose we take a random sample of 200 people in our city and find that 113 of them are planning "staycations." Let p = the proportion in our city who are planning staycations this year. A 98% confidence interval for P is a) (0.496, 0.634) b) (0.483, 0.646) c) No confidence interval is necessary, since we know p = 45%. d) (0.480, 0.648)