Not all restriction enzymes necessarily cleave DNA at rotationally symmetric sites For example XI is 5 CCANNNNN NTGG where the

Question

Not all restriction enzymes necessarily cleave DNA at rotationally symmetric sites For example XI is 5 CCANNNNN NTGG where the symbol represents the cleavage site and N means any nucleotide Make the simplifying assumptions that equal amouts of all four nucleotides exist in the human genome and that its base sequence is random How frequently would you expect the two ends of a single Bst XI cleaved human genomic DNA fragments to be compatible Recall that compatible ends can hybridize because they have complementary base pairs Multiple Choice O 1 1 048 576 DNA fragments will have compatible ends O1 256 DNA fragments will have compatible ends O 1 16 777 216 DNA fragments will have compatible ends OBst XI will cleave the DNA on average once in 65 536 base pairs one out 4096 DNA fragments will have compatible ends 14096 DNA fragments will have compatible ends O 1 1024 DNA fragments will have compatible ends 1 65 536 DNA fragments will have compatible ends

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