Question:
Rhea stated that the equation f(x) = x5 - 4x³ + x²-4 has 3
Last updated: 8/3/2022
![Rhea stated that the equation f(x) = x5 - 4x³ + x²-4 has 3](https://media.kunduz.com/media/sug-question/raw/81665505-1659485701.2561505.jpeg?h=512)
Rhea stated that the equation f(x) = x5 - 4x³ + x²-4 has 3 zeros because the graph only crosses the x-axis three times as pictured. Is she correct or incorrect? Explain to her why you think so.