Question:

s 1 ar th in of M L requires 0 5 g of NaOH for complete

Last updated: 7/4/2023

s 1 ar th in of M L requires 0 5 g of NaOH for complete

s 1 ar th in of M L requires 0 5 g of NaOH for complete neutralisation The number of replaceable hydrogen atoms and the molecular weight of A would be Mw of acid 96 a 2 94 d 4 92 b 1 95 c 3 93 55 A mixed solution of potassium hydroxide and sodium carbonate required 15 mL of an N 20 HCl solution when titrated with phenolphthalein as an indicator But the same amount of the solution when titrated with methyl orange as indicator required 25 mL of the same acid The amount of KOH present in the solution is a 0 014 g b 0 14 g c 0 028 g d 1 4 g 56 25 0 g of FeSO4 7H O was dissolved in water containing dilute H SO4 and the volume was made up to 1 0 L 25 0 mL of this solution required 20 mL of an N 10 KMnO solution for complete oxidation The percentage of FeSO4 7H O in the acid solution is 4 a 78 b 98 d 79 57 A 0 13 g of a specimen containing MnO is treated with iodide ions If iodine liberated requires 30 0 mL of 0 075 M solution of Na S O3 the percentage of MnO in the mineral is ho c 89 a 75 3 b 85 3 c 95 3 d None A Mod 58 The mass of K Cr O required to produce 5 0 L CO at 77 C and 0 82 atm pressure from excess of oxalic acid and volume of 0 1 N NaOH required to neutralise the CO evolved respectively are 24 31 a 7 g 2 86 L 101561 6 9 Boas b 5 g 1 86 L Jam d None c 4 g 0 86 L 59 A mixture of Na C O4 and KHC O4 H C O4 required equal o of 02 M KMnO and 0 2 M NaOH separately