Question:

S x 2x f 2x 3 3 1 2x 3 x 1 2 2x 3 3x 3 2x 3 2x 2 x x x 2 5x

Last updated: 10/28/2023

S x 2x f 2x 3 3 1 2x 3 x 1 2 2x 3 3x 3 2x 3 2x 2 x x x 2 5x

S x 2x f 2x 3 3 1 2x 3 x 1 2 2x 3 3x 3 2x 3 2x 2 x x x 2 5x 5 times the numerator and denominator by x 1