Question:
show that f'(x) = 2/4x-x^2 when g(f(x)) = x-2 and g'(x) = 2
Last updated: 8/4/2022
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show that f'(x) = 2/4x-x^2 when g(f(x)) = x-2 and g'(x) = 2 -[f(x)]^2
Last updated: 8/4/2022
show that f'(x) = 2/4x-x^2 when g(f(x)) = x-2 and g'(x) = 2 -[f(x)]^2