Question:
Solve the equation for the interval [0, 2π). 11) 2 sin²x =
Last updated: 8/7/2022
Solve the equation for the interval [0, 2π). 11) 2 sin²x = sin x A) x = 0, π, π/6, 5π/6 B) x = π/3 , 2π/3 C) x = π/6 , 5π/6 D) x = π/2 , 3π/2 , π/3 , 2π/3
Last updated: 8/7/2022
Solve the equation for the interval [0, 2π). 11) 2 sin²x = sin x A) x = 0, π, π/6, 5π/6 B) x = π/3 , 2π/3 C) x = π/6 , 5π/6 D) x = π/2 , 3π/2 , π/3 , 2π/3