Solve within invertal 0 < t < 2π. a) Let w = sin(t) so we

Last updated: 7/9/2022

Solve within invertal 0 < t < 2π. a) Let w = sin(t) so we can rewrite the equation as: b) Use Quadratic Formula to solve for w. That means: Write the negative root first. sin(t)= sin² (t) 1 = -6 sin(t) and sin(t) = c) Solve each equation for t within invertal [0, 2pi) using trig inverses: t= Round answers to 4 decimal places.