Question:
State the number of possible real zeros and turning points
Last updated: 7/17/2022
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State the number of possible real zeros and turning points of f(x) = x² - 6x + 8x5. Then determine all of the real zeros by factoring. 7 real zeros and 6 turning points; 0, 2, and 4 7 real zeros and 6 turning points; 0, –2, and –4 6 real zeros and 5 turning points; 0, 2, and 4 6 real zeros and 5 turning points; 0, -2, and —4