Step 3 our goal is to maximize the area A where A w 44w and

Last updated: 7/15/2023

Step 3 our goal is to maximize the area A where A w 44w and 0 w 44 So we recall the first derivative test for absolute extrema values which states that if c is a critical number of continuous function A defined on an interval then the following holds To apply this test we must first find A w Doing so gives the following result A W w 44w A W W If A w 0 for all w c and A w 0 for all w c then A c is the absolute maximum value of A If A w 0 for all w c and A w 0 for all w c then A c is the absolute minimum value of A Setting this derivative equal to 0 and solving for w gives the following result Applying the test we see that there is an absolute Select at this value of w