Question:

Suppose sinθ = 3/5, cosθ= 4/5 sin(2θ)=24/25 cos(2θ) =7/25

Last updated: 8/11/2022

Suppose sinθ = 3/5, cosθ= 4/5 sin(2θ)=24/25 cos(2θ) =7/25

Suppose sinθ = 3/5, cosθ= 4/5 sin(2θ)=24/25 cos(2θ) =7/25