Question:
The equation of the line tangent to the graph of f(x) =
Last updated: 7/17/2022
The equation of the line tangent to the graph of f(x) = 5¹-x² at x = 1 is y = -2x + 1. y = -2x + 3. y=-2(In 5)x+ 1. y = -2(In 5)(x-1) + 1.
Last updated: 7/17/2022
The equation of the line tangent to the graph of f(x) = 5¹-x² at x = 1 is y = -2x + 1. y = -2x + 3. y=-2(In 5)x+ 1. y = -2(In 5)(x-1) + 1.