The equilibrium constant for the following reaction:

Last updated: 8/6/2022

The equilibrium constant for the following reaction: Ca(HCO3)2(s) <--> CaO(s) + 2 CO₂(g) + H₂O(g) would be: O K = [CaO][CO₂]²[H₂O] / [Ca(HCO3)2] O K = [CO₂]²[H₂O] OK = [CO₂]²[H₂O] / [Ca(HCO3)2] O K = [Ca(HCO3)2] / [CaO][CO₂]²[H₂O]