The formula for the braking distance of a car is: d =V²/2g(f+ G) where: d is the braking distance (in feet) V is the initial

Question

The formula for the braking distance of a car is:
d =V²/2g(f+ G)
where:
d is the braking distance (in feet)
V is the initial velocity of the car (in feet per second)
G is the roadway grade (written in decimal form)
f is the coefficient of friction between the tires and the roadway
g is the acceleration constant due to gravity (32.2 ft/sec²)
a) If a car's speed was 47 miles per hour, what value would be used in this formula for V? Round to the
tenths place.
Recall 1 mile = 5280 feet.
feet per second
b) If a car was going 86 feet per second when the driver applied the brakes, on a road with grade
G = 0.03 and a coefficient of friction of f = 0.8, what distance would it go before stopping? Round to
the tenths place.
feet

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