The half-life of krypton-91 (Kr) is 10 s. At time t= 0 a

Last updated: 8/6/2022

The half-life of krypton-91 (Kr) is 10 s. At time t= 0 a heavy canister contains 4 g of this radioactive gas. (a) Find a function m(t) = m 2-t/h that models the amount of 91Kr remaining in the canister after t seconds. m(t) = 1 (2) 10 (b) Find a function m(t) = moet that models the amount of 91Kr remaining in the canister after t seconds. (Round your r value to five decimal places.) m(t) = (c) How much 91Kr remains after 1 min? (Round your answer to three decimal places.) ► (d) After how long will the amount of 91Kr remaining be reduced to 1 µg (1 microgram, or 10 -6 g)? (Round your answer to the nearest whole number.) sec