The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of

Question

The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 21.5 m/s is h = 2 + 21.5t - 4.9t2 after t seconds.
(a) Find the velocity (in m/s) after t seconds.
v(t) = 1.9
Find the velocity (in m/s) after 2 seconds and after 4 seconds.
v(2) = 1.9
m/s
m/s
V(4) = -17.7
(b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height?
v(t)
m/s
= 2.19
When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.)
S
(c) What is the maximum height (in m)? (Round your answer to two decimal places.)
25.58
m
(d) When (in s) does it hit the ground? (Round your answer to two decimal places.)
S
(e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.)
m/s

Kunduz · Accepted Answer

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