# The height (in meters) of a projectile shot vertically

Last updated: 7/11/2022

The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 21.5 m/s is h = 2 + 21.5t - 4.9t2 after t seconds. (a) Find the velocity (in m/s) after t seconds. v(t) = 1.9 Find the velocity (in m/s) after 2 seconds and after 4 seconds. v(2) = 1.9 m/s m/s V(4) = -17.7 (b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height? v(t) m/s = 2.19 When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) S (c) What is the maximum height (in m)? (Round your answer to two decimal places.) 25.58 m (d) When (in s) does it hit the ground? (Round your answer to two decimal places.) S (e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.) m/s