The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 80 feet per

Question

The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 80 feet per second is
f (t) = -16t² + 80t + 6.
(a) Verify that f(2)= f(3).
f(2)= 102
f(3) = 102
(b) According to Rolle's Theorem, what must be the velocity at some time in the interval (2, 3)?

Kunduz · Accepted Answer

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