Question:
The length of a rectangle is 9 yd more than twice the width
Last updated: 7/16/2022
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The length of a rectangle is 9 yd more than twice the width x. The area is 396 yd². Part 1 of 3 (a) Write an equation in terms of x that represents the given relationship. The equation is xx + 9x (yd) = 396(yd) Part: 1/3 Part 2 of 3 ☐=0 The width is X (b) Solve the equation to find the dimensions of the given shape. yd.