The pure, natural enantiomer of (-)-menthol, has an specific rotation [a]20 = -50° (Formula: (A-B)/(A+B) = ee = ap20/[a]020 -

Question

The pure, natural enantiomer of (-)-menthol, has an specific rotation [a]20 = -50°
(Formula: (A-B)/(A+B) = ee = ap20/[a]020 - show work!)
a) What is the ee of a mixture of 1.50 g (+)-menthol and 3.50 g (-)-menthol?
b) What is the rotation co2 of this mixture under standard conditions?

Kunduz · Accepted Answer

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