The zinc content of a 1 62 g ore sample was determined by

Last updated: 6/28/2023

The zinc content of a 1 62 g ore sample was determined by dissolving the ore in HCI which reacts with the zinc The excess HCI is then neutralized with with NaOH The reaction of HCI with Zn is shown Zn s 2HCl aq ZnCl aq H g The ore was dissolved in 150 ml of 0 600 M HCI and the resulting solution was diluted to a total volume of 300 mL A 20 0 ml aliquot of the final solution required 9 95 mL of 0 546 M NaOH to neutralize the excess HCI What is the mass percentage w w of Zn in the ore sample