To evaluate the integral ∫sin³θ cos⁶θ dθ by trigonometric

Last updated: 8/10/2022

To evaluate the integral ∫sin³θ cos⁶θ dθ by trigonometric transformation, we use the identity: (A) cos²θ = 1 + cos2θ / 2 (B) sin²θ = 1 - cos2θ / 2 (C) sinθ cosθ = sin2θ / 2 (D) sin²θ = 1 - cos²θ