Tutorial Exercise An augmented matrix for a system of linear

Last updated: 6/19/2023

Tutorial Exercise An augmented matrix for a system of linear equations in x y and z is given Find the solution of the system 1 1 3 3 0 4 19 0 360 Step 1 The solution of the system can be found using the Gauss Jordan elimination Recall that when using Gauss Jordan elimination the end goal is to obtain an identity matrix for the coefficient matrix by using elementary row operations Notice column 1 already has a 1 and then 2 zeros So next we focus on obtaining a 1 in row 2 column 2 This can be achieved by adding row 3 to row 2 and putting the result in row 2 1 1 3 37 1 1 3 3 0 4 19 0 0 3 60 0 3