v m s 4 3 2 1 tt A 1 s B 3 s C 4 s D 5 s 1 2 3 4 5 6 7 8 t s

Last updated: 6/10/2023

v m s 4 3 2 1 tt A 1 s B 3 s C 4 s D 5 s 1 2 3 4 5 6 7 8 t s O 3 The velocity v of an elevator moving upward between adjacent floors is shown as a function of time t in the graph above At which of the following times is the force exerted by the elevator floor on a passenger the least