Question:
wavelength 500 10 9 m d 1 10x10 4 m L 2 5 m x distance for
Last updated: 6/14/2023
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wavelength 500 10 9 m d 1 10x10 4 m L 2 5 m x distance for 1st dark minimum fringe 0 01136 m theta for dark minimum 0 260 degrees What is the width of the central maximum using sin approxim