We set up the ratio test as follows an 1 318 an lim x lim Step 7 lim 818 Step 6 Now we can simplify and evaluate the limit n 2 n

Question

We set up the ratio test as follows an 1 318 an lim x lim Step 7 lim 818 Step 6 Now we can simplify and evaluate the limit n 2 n n 1 1 x 4 n 2 x 1 4 n 1 Submit Skip you cannot come back 4 n 1 By the Ratio Test the series converges when lim 818 a n 1 an Jx n 0 positive number R such that the series converges if Ix al x 1 Therefore the radius of convergence is R

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