What is the hydronium ion concentration of a 0.200 M acetic acid solution with Ka = 1.8 x 10-5? The equation for the

Question

What is the hydronium ion concentration of a 0.200 M acetic acid solution with Ka = 1.8 x 10-5? The equation for the dissociation of acetic acid is: 
CH3CO2H(aq) + H₂O(I) =H3O+ (aq) + CH3CO2−(aq).
1.9 × 10-3 M
4.2 x 10-2 M
1.9 × 10-2 M
4.2 × 10-3 M

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