Question:
What is the inverse of the equation below? h(x) = -1/2
Last updated: 8/7/2022
What is the inverse of the equation below? h(x) = -1/2 log3(x) a) h-¹ (x)=3^(2x) b)h-¹(x) = 2(3)^x c)h-¹(x) = 2(logx 3) d)h-¹(x) = log3 (2x)
Last updated: 8/7/2022
What is the inverse of the equation below? h(x) = -1/2 log3(x) a) h-¹ (x)=3^(2x) b)h-¹(x) = 2(3)^x c)h-¹(x) = 2(logx 3) d)h-¹(x) = log3 (2x)