Question:

When 1 mol CrCl3 6H2O is treated with excess of AgNO3 3 mole

Last updated: 6/27/2023

When 1 mol CrCl3 6H2O is treated with excess of AgNO3 3 mole

When 1 mol CrCl3 6H2O is treated with excess of AgNO3 3 mole of AgCl are obtained The formula of the complex is Question Type Single Correct Type 1 CrCl3 H O 3 3H2O 2 CrCl H O 4 CI 2H 0 3 CrCl H 0 5 Cl H O