When 160. g of glycine (C₂H5NO₂) are dissolved in 1200. g of

Last updated: 7/10/2022

When 160. g of glycine (C₂H5NO₂) are dissolved in 1200. g of a certain mystery liquid X, the freezing point of the solution is 8.3 °C lower than the freezing point of pure X. On the other hand, when 160. g of ammonium chloride (NH4CI) are dissolved in the same mass of X, the freezing point of the solution is 20.5 °C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits.