When 200 0 mL of water is heated from 15 0 C to 40 0 C how much thermal energy is absorbed by the water Since the quantity of

Question

When 200 0 mL of water is heated from 15 0 C to 40 0 C how much thermal energy is absorbed by the water Since the quantity of heat equation is based on the mass of an object we must first determine the mass in kilograms of 200 0 mL of water To do this we use the density of water which is 1 0 g mL We then calculate the change in the temperature of the water using the equation AT T T Finally we use the quantity of heat equation Q mcAT along with the mass of the water m the specific heat capacity of water C and the change in temperature of the water AT to determine how much thermal energy is absorbed by the water Given V 200 0 mL T 15 0 C T 40 0 C C 4 18 x 10 J kg C Required Q Analysis AT T T Q mcAT 1g 1 mt Solution m 200 0 mt x m 0 2000 kg AT 1 2 T X 40 0 C 15 0 C 0 2000 kg 4 18 x 10 Q 2 09 x 10 J 1 kg 1000 g AT 25 0 C Now that we have calculated the mass of the water in kilograms and the change in temperature we may use these values to calculate the quantity of heat Q mcAT J kg 25 0 orbe 209 x 101 of thermal energy

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