Question:

When 3.52 g of bismuth oxide (molar mass = 465.96 g/ml)

Last updated: 7/31/2022

When 3.52 g of bismuth oxide (molar mass = 465.96 g/ml)

When 3.52 g of bismuth oxide (molar mass = 465.96 g/ml) reacts with excess carbon to form 2.90 g of bismuth metal (molar mass = 208.98 g/mol) according to the equation: Bi₂O3(s) + 3 C(s) → 2 Bi(s) + 3 CO(g) What is the percent yield of the reaction? (Answer to 1 decimal place)