Question:
When a monosaccharide forms a cyclic hemiacetal, the carbon
Last updated: 8/7/2022
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When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the ___________ carbon atom because Acetal; it forms bonds to an -OR and an -OR' Enantiomeric; depending on its position, the resulting ring can have a mirror image. OL: the carbonyl group is drawn to the left. D; the carbonyl group is drawn to the right. Anomeric; its substitutents can assume an alpha or beta