When an object moves along X axis under the action of force

Last updated: 7/6/2022

When an object moves along X axis under the action of force F = -kx it is said to be performing simple harmonic oscillatory motion about x=0 as mean position (here x is its x coordinate and k is a positive constant). Total energy of oscillation is equal to KA²/2 (Assume potential energy to be zero at mean position. Here A is amplitude of oscillation) If energy of oscillation is 18 J, between which points does the block will oscillate? A. between x = 0 and x = 4 m B. between x = -1m and x = 5 m C. between x = -2m and x = 6m D. between x = 1m and x = 3m