Question:
Write an equation for the conic in the xy-plane for (x')2
Last updated: 7/29/2022
Write an equation for the conic in the xy-plane for (x')2 /15 - (y')^2/6 =1 at θ=30 3x+42√3xy-39y²-360 = 0 3x²-12√3xy-39y²-360=0 -39x² +42-√3xy+3y² - 360 = 0 -9x² +42-√3xy-9y2² – 180 = 0