Question:

(x²+x)(x²-1)/(x²-4) ( x² +8x+12) (x²+x)(x²-1)/(x²-4) ( x²

Last updated: 7/20/2022

(x²+x)(x²-1)/(x²-4) ( x² +8x+12) (x²+x)(x²-1)/(x²-4) ( x²

(x²+x)(x²-1)/(x²-4) ( x² +8x+12) (x²+x)(x²-1)/(x²-4) ( x² +8x+12)= where x≠