Question:
Let θ = arctan(-√3/3), then A) θ = 5π/6 and tan θ = -√3/3 B)
Last updated: 8/4/2022
Let θ = arctan(-√3/3), then A) θ = 5π/6 and tan θ = -√3/3 B) θ = 11π/6 and tanθ = -√3/3 C) θ = -π/6 and tan θ = -√3/3 D) θ = -7π/6 and tanθ = -√3/3
Last updated: 8/4/2022
Let θ = arctan(-√3/3), then A) θ = 5π/6 and tan θ = -√3/3 B) θ = 11π/6 and tanθ = -√3/3 C) θ = -π/6 and tan θ = -√3/3 D) θ = -7π/6 and tanθ = -√3/3