(nedes ponedas (as duas 30- 25- Practice Problem 3: 15- T final 23.37°C AT T initial, acid = 17.78°C initial, base = 17.53°C 15

Question

(nedes ponedas (as duas
30-
25-
Practice Problem 3:
15-
T final
23.37°C
AT
T
initial, acid
= 17.78°C
initial, base
= 17.53°C
15
20
10
time (minutes)
50.00 mL of a 0.687 M HCl is combined with 50.00 mL of
0.752 M NaOH. Using the data from the above graph,
calculate the average initial temperature. Then calculate the
molar enthalpy of neutralization in kJ/mol. Assume the
neutralized solution has a specific heat of 3.90 J/gºC and a
density of 1.013 g/mL. Hint: You need to identify the
limiting reactant and divide the moles of limiting reactant by
its coefficient to determine the moles of reaction.
All practice problems must be solved and written in your
lab notebook prior to lab.
Laboratory Report
Cover Sheet
Data Sheet
●
Answer: -65.7 kJ/mol
● 3 Graphs
• Post-lab Sheet
I
References
(1) Silberberg, M. Chemistry: The Molecular Nature of
Matter and Change, 9th ed.; McGraw-Hill: New York,
NY, 2021.
(2) Halpin, J. General Chemistry I, Lecture Notes.

Kunduz · Accepted Answer

Click to see the answer