Question:

1 2 3 4 ARJUNA JEE Mole Concept Continued Based on the

Last updated: 7/3/2023

1 2 3 4 ARJUNA JEE Mole Concept Continued Based on the

1 2 3 4 ARJUNA JEE Mole Concept Continued Based on the following consecutive reactions 2KCIO 2KCI 30 4A1 30 2Al O3 2 moles of KCIO of 50 purity on strong heating and then with excess of Al Al2O3 formed is A 2 mol C 3 mol In the following set of reactions CaCO CaO CO 75 yield CO C2CO 50 yield CO formed at STP from 10 g of CaCO is A 2 24 L B 11 2 L C 1 12 L D 1 68 L II III B 1 mol D 1 5 mol NH is formed in the following step Ca 2C CaC 50 yield L CaC N CaCN C 100 yield CaCN 3H 0 2NH3 CaCO 50 yield 2 moles of NH are formed if we take A 1 mol Ca B 2 mol Ca C 3 mol Ca D 4 mol Ca What weights of P O and P O will be produced by the combustion of 31 g of P in 32 g of oxygen leaving no Pa and O A 2 75 g 219 5 g B 27 5 g 35 5 g C 55 g 71 g D 17 5 g 190 5 g 5 How many moles of P4O6 and P4O10 will be produced by the combustion of 12 4 gm of phosphorus in 12 8 gm of Oz leaving no Pa or 0 Atomic wt P 31 A 0 11 mol and 0 3 mol B 0 15 mol and 0 25 mol C 0 05 mol each D 0 1 mol each 6 If we start from 500 g of CaCO3 and treated with series of reagents to give C H o find mass of CsH formed if molar mass of CaCO is 100g and CsHio is 58 g B 116 g A 58 g C 168 g D 224 g 7 For sequential reaction A B C 2B C 2D If yield of i and ii reactions are 90 and 80 respectively then the overall yield is expected to be A 90 C 72 A 42 gm C 14 3 gm i ii B 80 D 10 8 NX is produced by the following step of reactions M X MX 3MX2 X M Xs MiXs N CO3 NX CO M 0 How much M metal is consumed to produces 206 gm of NX Take at Wt of M 56 N 23 X 80 B C Z F A 3 moles C 5 moles DPP 07 B 56 gm D 7 4 gm 5 moles of A 6 moles of Z are mixed with sufficient amount of C to finally produce F Then find the maximum moles of F which can be produced Assuming that the product formed can also be reused Reactions are A 22 1 B 4 5 moles D 6 moles 10 Human lungs can absorb 8 gm O per hour by respiration If all oxygen atoms are converted to carbohydrates C6H12O6 how long will it take to produce 180 gm C6H12O6 A 8 hours B 12 hours C 10 hours D 6 hours