Question:
A 13.7 kg mass is suspended on a 1 x 10^5 N/m spring. The
Last updated: 7/10/2022
A 13.7 kg mass is suspended on a 1 x 10^5 N/m spring. The mass oscillates up and down from the equilibrium position yeq = 0 according to y(t) = A sin(wt + θ0). At time to=0 the mass is at 29.6 cm and moving upward at velocity +6.32 m/s.