A triangular lot bounded by three streets has a length of

Last updated: 7/10/2022

A triangular lot bounded by three streets has a length of 300 feet on one street, 250 feet on the second, and 420 feet on the third. Find the measure of the largest angle formed by these streets. Which of the following equations can be used to solve the problem? 250^2=300^2 +420^2 - (2)(300)(420)cosx 300^2 = 250^2 + 420^2 - (2)(250)(420)cosx 420^2 = 300^2 + 250^2 - (2)(300)(250)cosx