Solution of triangles Questions and Answers

Triangle 1 has an angle measure 26° and an angle measures 53°. Triangle 2 has an angle that measures a where at # 53°. Based on the information, Frank claims that triangle 1 and triangle 2 cannot be similar. What value of will refute franks claim?

The triangle will be rotated by 180° clockwise around the point (3, 4) to create the triangle A'B'C'. Indicate whether each of the listed features of the image will or will not be the same as the corresponding feature in the original triangle by selecting the appropriate box in the table.

Solve the triangle. Round to the nearest tenth. In AEFD, f = 29, d = 21, e = 13 mZE = 25°, mZF = 131°, mZD = 24° None of the other answers are correct mZE = 30°, m≤F = 110º, m≤D = 40° mZE=24°, mZF = 115°, mZD = 41° mZE=25°, m<F = 111°, mZD=44°

Determine the measure of side d in the following diagram. Make sure that your answer is rounded to the nearest tenth.

Determine whether the Law of Sines or the Law of Cosines is needed to solve the triangle. B = 13°, a = 155, b = 62 Law of Sines Law of Cosines Solve (if possible) the triangle. If two solutions exist, find both. Round your answers to two decimal places. (If two solutions exist, enter the solution set with the smaller A-value first. If a triangle is not possible, enter IMPOSSIBLE in each corresponding answer blank.)

Think About the Process In AABC, mZB is 5 times mZA and mZC is 16° less than 4 times mZA. What equation is used to solve for the variable x? Find the measure of each angle. The figure is not drawn to scale. Which of the following is the correct equation used to solve for the measure of each angle? A. MZA+mZB+mZC= 180° B. MZA-mZB-m/C= 180° C. MZA-mZB+mZC = 180° D. MZA+mZB-mZC= 180°

Use the Law of Cosines to solve the triangle. Round your answers to two decimal places. a = 11, b = 15, c = 21

Use Heron's Area Formula to find the area of the triangle. (Round your answer to two decimal places.) A = 80°, b = 74, c = 42

Use the Law of Sines to solve (if possible) the triangle. If two solutions exist, find both. Round your answers to two decimal places. A = 22° 32', a = 9.5, b = 22 Case 1: B = C = C= (smaller B-value) Case 2: B = C = C= (larger B-value)

In the figure, m∠1 = (7x+7)°, m∠2 = (5x+14)°, and m∠4 = (13x +9)°. Your friend incorrectly says that m∠4 = 15°. What is m∠4? What mistake might your friend have made?

Use the Law of Sines to solve the triangle. Round your answers to two decimal places. A = 20.1°, C = 51.2°, C = 2.2 B = a = b=

Find the area of the triangle. Round your answer to one decimal place. A = 66⁰, B = 43°, a = 7

Determine whether the Law of Sines or the Law of Cosines is needed to solve the triangle. A = 41°, B = 36°, c = 3.6 O Law of Sines O Law of Cosines Solve (if possible) the triangle. If two solutions exist, find both. Round your answers to two decimal places. (If a triangle is not possible, enter IMPOSSIBLE in each corresponding answer blank.) C= a= b=

Determine whether the Law of Sines or the Law of Cosines is needed to solve the triangle. a = 12, b = 14, c = 8 Law of Sines Law of Cosines Solve (if possible) the triangle. If two solutions exist, find both. Round your answers to two decimal places. (If a triangle is not possible, enter IMPOSSIBLE in each corresponding answer blank.) A = B = C =

Solve ΔABC, given A=43°, a = 2.5 cm, and b= 3.6 cm. Begin by sketching and labeling a diagram. Account for all possible solutions. Express each angle to the nearest degree and each length to the nearest tenth of a unit.

Solve the following triangle. B= 20°, C= 50°, b=3