A vase can be modeled using x^2 / 5.5225 - (y-5)^2 / 42.25

Last updated: 7/8/2022

A vase can be modeled using x^2 / 5.5225 - (y-5)^2 / 42.25 = 1 and the x-axis, for 0 ≤ y ≤ 20, where the measurements are in inches. Using the graph, what is the distance across the base of the vase, and how does it relate to the hyperbola? 5.93 inches; distance between the x-intercepts 4.50 inches; length of the transverse axis 2.97 inches; distance between the intercepts 2.35 inches; length of the transverse axis