Confirm that magnesium is the limiting reagent in this reaction by showing that all the magnesium is consumed, and some of the

Question

Confirm that magnesium is the limiting reagent in this reaction by showing that all the
magnesium is consumed, and some of the HCI is left over. Remember that the limiting
reagent is always completely used up and there will always be some of the excess
reagent unreacted.
For this example let's assume that 0.116 g of magnesium are used. The amount of
hydrochloric acid used is the same in all experiments, 4 mL of 6 M hydrochloric acid.
Mg(s) + 2 HCI (aq) →
MgCl₂ (aq) + H₂(g)
In this reaction there are
moles of magnesium and
moles of hydrochloric acid. Because HCI has a coefficient of 2 in
this equation, we understand that 2 moles of HCI are required to react for every 1
mole of magnesium that reacts. We observed that all of the magnesium was used so
we know, from the equation, that the moles of HCI used must be 2 X moles of
magnesium used. To find the amount of HCI left over, we do the following:
"moles of HCI added" - 2 X "moles of magnesium added" = moles of HCI
in excess.

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