Question:
Given: H₂(g) + Br₂(1)→ 2 HBr(g) ΔHx= -72.8 kJ Calculate the
Last updated: 8/9/2022
![Given: H₂(g) + Br₂(1)→ 2 HBr(g) ΔHx= -72.8 kJ Calculate the](https://media.kunduz.com/media/sug-question/raw/71768168-1660059416.6900642.jpeg?h=512)
Given: H₂(g) + Br₂(1)→ 2 HBr(g) ΔHx= -72.8 kJ Calculate the amount of energy absorbed or released when 15.0 g of HBr(g) is formed. 4.85 kJ absorbed 6.75 kJ released 13.5 kJ released 607 kJ absorbed