Question:

Given the ends of the diameter of a circle at (-3,11) and

Last updated: 7/15/2022

Given the ends of the diameter of a circle at (-3,11) and

Given the ends of the diameter of a circle at (-3,11) and (3,-13), what is the standard form of the equation of the circle? Ox² + (y - 3)2 = 153 ○ (x-4)² + (y + 3)² = 125 x² + (y - 3)² = 13