Given the information below, what is the change in enthalpy

Last updated: 7/30/2022

Given the information below, what is the change in enthalpy (in kJ) when 1.32 x 105 kg of liquid H₂ is burned? 2 H₂ (/)+02 (1)→ 2 H₂O (/) ΔH'rxn=-571.6 kJ a-3.74 x 1010 b.-285.8 Oc-571.6 d.-1.87 x 1010