How many mL of 0.757 M HI are needed to dissolve 8.55 g of

Last updated: 7/29/2022

How many mL of 0.757 M HI are needed to dissolve 8.55 g of MgCO3? 2HI(aq) + MgCO3(s)→→→ MgI₂(aq) + H₂O(1) + CO₂(g) mL