Question:
The enthalpy of neutralization of HCI and NaOH is 57 kJ mol
Last updated: 7/3/2023
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The enthalpy of neutralization of HCI and NaOH is 57 kJ mol The heat evolved at constant pressure in kJ when 0 5 mole of H SO4 react with 0 75 mole of NaOH is equal to B 57x0 5 D 57x0 25 3 A 57x 4 C 57 SPACE FOR ROUGH WORK