Question:

The enthalpy of neutralization of HCI and NaOH is 57 kJ mol

Last updated: 7/3/2023

The enthalpy of neutralization of HCI and NaOH is 57 kJ mol

The enthalpy of neutralization of HCI and NaOH is 57 kJ mol The heat evolved at constant pressure in kJ when 0 5 mole of H SO4 react with 0 75 mole of NaOH is equal to B 57x0 5 D 57x0 25 3 A 57x 4 C 57 SPACE FOR ROUGH WORK